1.79t^2-26.1t-26.1=0

Solution for 1.79t^2-26.1t-26.1=0 equation:

1.79t^2-26.1t-26.1=0

a = 1.79; b = -26.1; c = -26.1;
Δ = b2-4ac
Δ = -26.12-4·1.79·(-26.1)
Δ = 868.086
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26.1)-\sqrt{868.086}}{2*1.79}=\frac{26.1-\sqrt{868.086}}{3.58}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26.1)+\sqrt{868.086}}{2*1.79}=\frac{26.1+\sqrt{868.086}}{3.58}
$